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((4.5*10^-4)x)-((.295x))=0
We add all the numbers together, and all the variables
((4.5*10^-4)x)-((+.295x))=0
We calculate terms in parentheses: +((4.5*10^-4)x), so:
(4.5*10^-4)x
We multiply parentheses
45x^2-4x
Back to the equation:
+(45x^2-4x)
We calculate terms in parentheses: -((+.295x)), so:We add all the numbers together, and all the variables
(+.295x)
We get rid of parentheses
.295x
Back to the equation:
-(.295x)
(45x^2-4x)-(+.295x)=0
We get rid of parentheses
45x^2-4x-.295x=0
We add all the numbers together, and all the variables
45x^2-4.295x=0
a = 45; b = -4.295; c = 0;
Δ = b2-4ac
Δ = -4.2952-4·45·0
Δ = 18.447025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.295)-\sqrt{18.447025}}{2*45}=\frac{4.295-\sqrt{18.447025}}{90} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.295)+\sqrt{18.447025}}{2*45}=\frac{4.295+\sqrt{18.447025}}{90} $
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